Soumendra M. answered 01/17/17
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Learn and Enjoy Math-Phy-CS-EE
I am assuming the car is at the pick of the hill, as you mentioned that it is crossing over.
Forces on the car along vertical direction are Fn(up), mg(down)
centripetal force mv^2/r = mg -Fn
Fn = mg - mv^2/r = m ( g - v^2r/2) = 1145 * (9.8 - 15 * 15 /(2 *34) ) = 7432