Farrooh F. answered 01/15/17
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Let f(t) be the function for the formula of machine value in t years.
We know that today it costs 120,000. Mathematically this means, at t = 0, f(t) = 120,000, or f(0) = 120,000.
Next, we know that in 10 years, it will cost 4,000 only. Again, mathematically this means, at t = 10, f(t) = 4,000, or f(10) = 4,000.
Now any function of a line can be written as f(t) = m t + b, where one needs to determine constants m and b. From equations above we already know that
f(0) = 120, 000
m*0 + b = 120, 000
b = 120, 000
Now we know b. From the second equation we can write:
f(10) = 4,000
m*10 + 120,000 = 4,000
10 m = -116,000
m = -11,600
Finally:
f(t) = -11,600 t + 120,000
Now using this nice formula, we can replact t with 8, i.e. t = 8, and solve for f(8):
f(8) = -11,600*8 + 120,000 = 27,200
We know that today it costs 120,000. Mathematically this means, at t = 0, f(t) = 120,000, or f(0) = 120,000.
Next, we know that in 10 years, it will cost 4,000 only. Again, mathematically this means, at t = 10, f(t) = 4,000, or f(10) = 4,000.
Now any function of a line can be written as f(t) = m t + b, where one needs to determine constants m and b. From equations above we already know that
f(0) = 120, 000
m*0 + b = 120, 000
b = 120, 000
Now we know b. From the second equation we can write:
f(10) = 4,000
m*10 + 120,000 = 4,000
10 m = -116,000
m = -11,600
Finally:
f(t) = -11,600 t + 120,000
Now using this nice formula, we can replact t with 8, i.e. t = 8, and solve for f(8):
f(8) = -11,600*8 + 120,000 = 27,200