
Dalia C. answered 01/12/17
Tutor
4.8
(31)
Highly Qualified Mathematics and Physics for grades 7-12 in CT.
Let Mr. Nelson's age be m, and his son John be j:
Then, the first equation is
m=9j , Mr. Nelson is 9 times his son's age currently.
In 9 years, there is a new equation
m+9=3(j+9), Mr Nelson will be 3 times his son's age in 9 years.
Simplifying the second equation, gives:
m=3j+18
Subtract the two equations to eliminate m (it's easiest), gives:
0=6j-18
Solve for j to get
18=6j
3=j
The son is currently 3 years old, so Mr. Nelson who is 9 times his son's age currently is 27 years old, or,
m=9j=9*3=27