solve -12cosx+6=0 in the interval [0,2pi)

Question

A. pi/3, 2pi/3

B. pi/6, 11pi/6

C. pi/3, 5pi/3

D. 2pi/3, 4pi/3

Answer 1

-12cos(x)+6=0

-12cos(x)=-6

cos(x)=-6/-12

cos(x)=1/2 when x = pi/3 or 5pi/3....[C]