Using vertical movement against gravity
h= ut -1/2(gt2 )
comparing with the function given
f(t) = 16t2 +80t
= 80t + 16t2
this gives u = initial veocity = 80ft/sec
g = -32ft/sce2 - sign due to upward motion
using V2 = u2 +2gh
0= u2 - 32h
u2 = 80x80 = 32 h
gives h= 6400/64 = 100ft (Ans)
for time in air
v = u +gt
v=0 at highest point
u-32 t =0
80= 32 t
t= 80/32=2.5 sec Time the ball remains in air (Ans)
The time ball is in air =2.5+2.5 = 5 Sec. (up and down time) (Ans)
The shape of the graph will be a parabola
y= 16x2 +80x passing through origin