how would I graph this is slope point form

Question

m=3-(-3)/3-0=6/3 =2 slope=2    original points (3,3) (0.-3)

second points

y-(-3)=2(x-0)

y+3=2x slope intercept form

first points

y-3=2(x-3)

y-3=2x-6

Answer 1

y=2x-3 is slope intercept form y=mx+b with m=2=slope, b=-3=intercept

plot (3,3) and (0,-3) then draw a straight line through them, put arrows at the end of both ends of the line to indicate the line goes forever and ever, That's the graph of the equation