ROLLES THEOREM

Question

The function f(x)= x^2/3 takes on the same values at x= -1 and at x= 1. According to ROLLES THEOREM there should be a point C in the open interval (-1,1) where f1(c)=0 , I need help finding such point

Answer 1

f is not differentiable on the interval (-1,1) because f' is undefined when x = 0 (the cube root of x is in the denominator of f'), so the conditions of Rolle's Theorem are not met.