can someone help me please

Question

Suppose f(x)= 34.0+1.3log(x+1) models salinity of water to depth of 1000 meters at a certain latitude. X is the depth in meters and f(x) is in grams of salt per kilograms of seawater. Approximate the depth (to the nearest tenth of a meter) where the salinity equals 37. 

Answer 1

f(x)= 34.0 + 1.3 log(x+1)

 

You seek x where f(x) = 37

 

37 = 34.0 + 1.3 log(x+1)

 

3 = 1.3 log(x + 1)

 

2.3077 = log(x + 1)

 

10^2.3077 = x + 1

 

x = 10^2.3077 - 1 = 202.096

 

x ≅ 202.1 m