Kenneth S. answered • 12/08/16
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Let's cut to the chase: I know this subject & how to teach YOU
BAD NEWS! It's not a circle, it's an ellipse!
Delete the coefficient 4 and replace it by division by ¼, and then you will see that this is an ellipse with a=1 (a squared is the denominator (invisible) associated with the y-related term) and b = square root of ¼.
Center: (0,1)
Major axis runs vertically through center and minor axis runs horizontally through center.
Kenneth S.
The equation is equivalent t x2/¼) +(y-1)2/1=1 and you compare it to (x-h)2/b2 + (y-k)2/a2 = 1 and match the specific numbers for b squared, a squared and h & k to have all you need to correctly graph & identify this ellipse. Consult your textbook.
Do you understand that removal of the coefficient 4 (replaced by division by one fourth) is how to identify b squared?
BTW, if the larger denominator were beneath the x-related term, then the major axis would run horizontally through center (h,k).
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12/08/16
Jesse K.
Thanks a lot. Now I understand
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12/09/16
Germin R.
12/08/16