
Arturo O. answered 12/06/16
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ac = v2/r
v = tangential speed
ω = angular rate of rotation of the merry-go-round, which is the same everywhere on the merry-go-round
v = ωr
Then
ac = (ωr)2/r = ω2r
The person farther from the center experiences a higher centripetal acceleration. Sue is correct. Mark was right about the inverse relation with r, but neglected the direct relation with v2.

Steven W.
12/06/16