Michael J. answered 12/04/16
Tutor
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Understanding the Principles and Basics with Analysis
Let x, y, and z be the real roots, since we have a cubic polynomial that has at most 3 real roots.
xyz = 14 eq1
x + y + z = 4 eq2
The factors of 14 are 1, 2, 7, and 14.
What if we try this combination,
(-1)(-2)(7) = 14
-1 + (-2) + 7 = 4
This works out!
The roots are then -2, -1, and 7.
Your polynomial is then
f(x) = (x + 1)(x + 2)(x - 7)