
Arturo O. answered 12/03/16
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I will set this up for you and you can crunch out the numbers.
Re = mean radius of earth (given)
h = altitude above earth's surface (given)
R = radius of circular orbit = Re + h
M = mass of earth (look up)
G = universal constant of gravitation (look up)
Then the magnitude of the centripetal acceleration that keeps the body in an orbit of radius R around the earth is
a = GM/R2 = GM / (Re + h)2
There is another way to solve this using Kepler's third law, if you are interested, but it is more complicated.