physics homework help

Question

A milk carton with a mass of 2.00 KG is pulled across a table with a horizontal force of 3.00 N. if the coefficient of friction is 0.110, what is the acceleration of the milk carton? Show your work.

Answer 1

a = F/m (Newton's 2nd law)

 

T = applied force = 3.00 N

 

f = friction force = μmg

F = net force = T - f

 

F = [3.00 - (0.110)(2.00)(9.81)] N ≅ 0.842 N

a = 0.842 N / (2.00 kg) = 0.421 m/s²