physics homework help

Question

A ball rolls horizontally off a table with an initial speed of 2.45 m/s. The ball struck the floor with a horizontal displacement from the table of 1.3 m determine the height of the table. Show all your work please.

Answer 1

This problem can be solved if we know the value of coefficient of friction on the floor 

 

1/2mu² +mgh = KE when strikes the floor

where u = initial velosity 2.45 m/s

 

Force exerted by the rough surface of the floor = coefficient of friction x mass x g

 

so acceleration = - coefficient of friction x g

 

Final velocity being zero on floor

 

m/2(2.45x2.45 )+mgh- coefficient of friction x mg x distance it moves on the floor = 0

 

1/2 (2.45x2.45) +gh - coefficient of friction x g x 1.3 =0  From here h can be found