Physics honework

Question

A man walked 440 m [ 50.0°] ( polar positive) and then 580 m [185°] (polar positive). The entire trip took 150.0 min. what was the total distance travelled? And what was the displacement of the man?

Answer 1

The total distance travelled was 440 m+ 580 m.

The mention of the total time seems irrelevant, since there's no rate usage in this problem.

As for displacement, that can be computed using a diagram and the Law of Cosines.  That I leave to you.