Momentum And Collision 7

Question

A bullet is accelerated down the barrel of a gun by hot gases produced in the combustion of gun powder. What is the average force (in N) exerted on a 0.0200 kg bullet to accelerate it to a speed of 575 m/s in a time of 4.60 ms (milliseconds)? (Enter the magnitude.)

N

Answer 1

F = ma

 

a = Δv/Δt = [(575 - 0) m/s] / [(4.60 x 10^-3) s] = 125,000 m/s²

 

m = 0.0200 kg

 

F = ma = (0.0200)(125,000) kg m/s² =  2500 N