Raymond B. answered 03/11/20
Math, microeconomics or criminal justice
Just a guess but usually squares and circles have the maximum area for given perimeter
Let W=L = 2r W=width, L=length and r = semi-circle radius
then Area = 2r(2r) + pi(r)2 = (4+pi)r2 where 40 = 4r+2rpi = (4+2pi)r
solve for r= 40/(4+2pi) = about 3.9
2r = W = L = 7.8 km