Simplifying fractions with radicals

Question

In Algebra 1 I am given the following problem:

 

Simplify: (9 - 2√5) / √3

Please help me.

Answer 1

(9 - 2√5) / √3

(9 - 2√5)(√3) / (√3)(√3)        multiply numerator and denominator by √3

(9√3 - 2√15) / 3                    simplify

Answer 2

To simplify, you have to find a way to eliminate the radicals in the denominator.

 

[(9-2√5)/√3][√3/√3]   multiply by 1 (√3/√3)

 

[9√3-2√(3*5)]/(√3)² = [9√3 - 2√15]/3 = 3√3 - (2/3)√15