Hemang S.

asked • 11/15/16

Physics question

Q A box weighting 20 kg is pushed along the floor at a constant speed by applying horizontal force. If the coefficient of friction is 0.25 then force applied is...?

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Arturo O. answered • 11/15/16

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The applied force must be in equilibrium with the force of friction.  
 
F = applied force
f = force of friction 
 
F = f
f = μmg = (0.25)(20 kg)(9.81 m/s2) = 49.05 N
 
F = 49.05 N
 
By the way, the box does not weight 20 kg.  20 kg is it mass m.  Its weight is mg.
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Hemang S.

Option for this question aee.
1.5N.               2.10N
3.50N.             4.200N
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11/15/16

Arturo O.

Given the information in the problem statement, the solution is correct.
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11/15/16

Hemang S.

You are right value of g=10m/s2
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11/16/16

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