Robert D. answered 11/13/16
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Math/MATLAB/Electrical Engineering Tutor
y=2-log(100-x)/0.30
y=3
substitute the value of y
log(100-x)/0.30=1
log(100-x)=0.30
case 1
I assume the log is 10 based
100-x=10^(.3)=2(approx)
so x= 98%
If log is natural logarithm
l100-x=e^.3=1.35 so =98.65 i.e 99%