Kenneth S. answered 11/10/16
Tutor
4.8
(62)
Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
y = ¼cot(x-pi/2) has the same period as y = cot x but it's shifted to the right by pi/2.
So the period is pi. Normal vertical asymptotes for y = cot x are based on sin x in denominator (cot x = cos x / sin x) and would have V.A. at 0 and pi etc. but these V.A.s are shifted to x = pi/2 and 3pi/2, etc in this case... Two more V.A.s are
x=-pi/2 and x = -(3/2)pi.
x-intercepts(when y = 0) occur when cos (x-pi/2) so that means x = 0 ± any multiple of pi...e.g.
Consult your calculator or textbook or Google graphs of cotangent function for hints on graphing.