
Steve S. answered 02/04/14
Tutor
5
(3)
Tutoring in Precalculus, Trig, and Differential Calculus
x+3=√(153-x)
Square both sides:
x^2 + 6x + 9 = 153 - x
x^2 + 7x - 144 = 0
(x + 16)(x - 9) = 0
x = -16 or x = 9
check:
(-16)+3 =? √(153-(-16))
-13 =? √(169))
-13 ≠ 13 so x = -16 is NOT a solution.
(9)+3 =? √(153-(9))
12 =? √(144)
12 = 12 so x = 9 IS a solution
Richard A.
02/04/14