Mariel M.

asked • 11/06/16

what are the coefficients?

what are the coefficients?
A horizontal/vertical ellipse or hyperbola use the general form Ax^2+Cy^2+Dx+Ey+F=0Ax2+Cy2+Dx+Ey+F=0. Solving for 5 unknowns (A, B, C, D, E, F) requires 5 equations, needs 5 points given. But if one of the coefficients is divided out (A or C), then only 4 coefficients remain and only 4 points are needed. x^2+Cy^2+Dx+Ey+F=0x2+Cy2+Dx+Ey+F=0

Given 4 points on a horizontal ellipse (3.75, 0), (0, 2.71), (1, -7), and (-1, -5.725). Select the missing coefficients (answers have been rounded to the nearest tenth).

_x2 + _y2 + _x + _y + _ = 0

Neal D.

Mariel,
 
Do you use a graphing calculator?
Do you work with matrices?
If so, this problem is relatively easy.
 
Neal
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11/06/16

Raymond B.

true, but only if tedious is easy, and you avoid nearly inevitable mistakes along the way
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12d

1 Expert Answer

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Raymond B. answered • 12d

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