distance and midpoint of line segment.

Question

Please help find the distance between the points, and the( midpoint) of the line segment. For the midpoint I need the the coordinates, not the distance between the end of the segment and the midpoint.

-(2/3),(3/2) , (7/3), (2)

Thanks much for your help, If you can please show steps so I understand this. 

Answer 1

Hi Sammy, the distance between two points is given by the formula:

 

d = √( (x₂ - x₁)² + (y₂ - y₁)² )

 

Let (x₁, y₁) be (-2/3, 3/2).

 

Let (x₂, y₂) be (7/3, 2)

 

Distance:

 

d = √( (7/3 - (-2/3))² + (2 - 3/2)²

 

d = √( (9/3)² + (1/2)² )

 

d = √( 9 + 1/4 [written as .25])

 

d = √9.25

 

d ≈ 3.04

 

Midpoint:

 

m = ( (x₁ + x₂) / 2, (y₁ + y₂) / 2 )

 

m = ( (-2/3 + 7/3 / 2, (3/2 + 2) / 2 )

 

m = (5/6, 7/4)

 

Questions?