
Sally D. answered 10/30/16
Tutor
5
(4)
Patient and Professional USNA Grad for Writing, Math, and More!
Hey Ashley!
We can set up an algebraic equation to represent this problem.
Let x represent the number of quarters you have, and y represent the number of dimes you have. We know from the problem that we have 5 more dimes than quarters, so y can also be represented as x+5. We also know that a dime is worth .10 and a quarter .25.
Therefore the following equation represents the amount of money we have:
.10(x+5) + .25x = 2.95
Now we solve for X
.10x + .5 + .25x = 2.95
.35x = 2.45 (here's that one variable equation in its simplest form!)
x = 7, you have seven quarters.
Since we know we have 5 more dimes than quarters, by adding 7 to x, we get 12.
You have 12 dimes and 7 quarters.