Inactive Tutor answered 10/29/16
Tutor
New to Wyzant
Hi Javier,
This takes some trial and error and an understanding of the properties of logarithms.
We do know that "the log of a quotient equals the difference of the logs".
So perhaps loga20/5 = loga20 - loga5 will lead somewhere. Notice that the loga20/5 = loga4.
The loga4 = loga22 = 2loga2 (another property of logs).
Putting that all together we have loga20 - loga5 = 2loga2.
Substituting what is given we have: b - c = 2loga2. Or, loga2= (b-c)/2