Hello, thank you for taking the time to post your question!
The underlying equation that you want to use here is the point-slope form of a linear equation:
y−y1=m(x−x1)
For this set of values, we have a point (x1,y1)=(4,2) and a line perpendicular to y=−4/3x−4 ... a perpendicular line has a slope that is the negative reciprocal of the original slope. To find this, you flip the fraction and change the sign. m=−1/(−4/3)=3/4
Now that you have the new slope (m=3/4) and the point (4,2), you can plug these values into the point-slope form: y−2=3/4(x−4)
Finally then, to get the equation in the y=mx+b format, you can distribute the slope and then solve for y: y−2=3/4x−3/4(4)
y−2=3/4x−3
y=3/4x−3+2
y=3/4x−1 , so that would be your slope-intercept form on this one
I hope that helps you get moving in a better direction on this type of question! Feel free to reach out if you have any additional questions beyond that :)
