(2,-2) slope=2 how to put it in slope intercept form

Question

i cnt figure out how to do this

Answer 1

The equation of a line is

y-y1=m(x-x1) ,where y1 is your y-cord, m is your slope and x1 is your x-cord.

the information you provided was m=2, (2,-2)

now plug in

y-(-2)=2(x-2)

now solve for y to put it in the form of y=mx+b where m is your slope and b is your y intercept

y+2=2x-4

y=2x-6

Answer 2

The equation of a line is given by:

y = mx + b

where m = slope = 2 and therefore y = 2x + b.  Since x = 2 and y = -2 (this is given by the point at (2,-2)), you can solve for b:

 

-2 = 2(2) + b

-2 = 4 + b

-6 = b

 

Thus the equation of the line that passes through the point (2, -2) and has slope = 2 is

 

y = 2x - 6

 

Answer 3

Hello my name is Jose Ramirez from El Paso Texas. 

I can help yuo...

two ways to answers this. 

Y=mx plussign b

(2,-2) M=2 Substitude and Point intersept and slope

slove for b?

-2=2(2)plus sign b

-2=4plus sign b

-2-4=b

-6=b

final y=2x-6