
Arturo O. answered 10/24/16
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T = pull = 27.4 N [given]
θ = angle of pull above horizontal = 35º [given]
m = mass = 11.4 kg
Fn = normal force = ?
Assume up is (+) and down is (-). Set up equilibrium of forces in vertical direction and solve for Fn:
Tsinθ + Fn = mg
Fn = mg - Tsinθ = [(11.4)(9.8) - (27.4)sin(35°)] N = 96.00 N