find the number of 15 cenitimeter square tilesrequired to cover a rectungular floor 5.5 m long and 4.05 m wide

Question

find the number of 15 cenitimeter square tilesrequired to cover a rectungular floor 5.5 m long and 4.05 m wide

 

Answer 1

The solution to this problem may not be simply an area computation.  This is because cutting/breaking 15-cm square tiles produces "waste" (unless you install really ugly scraps).

 

The floor is:

    5.5m long = 550 cm = 550/15 tiles = 36.67 tiles   (so, 37 tiles with 1/3 of last tile "wasted" -- we don't want to use two 1/3-tiles to make a needed 2/3-tile)

    4.05 m wide = 405 cm = 405/15 tiles = 27 tiles (even)

 

37*27 = 999 tiles

 

[Now -- be realistic -- if this is simply an area problem, both the length and the width would be an integer multiple of tiles, not just the width.]

Answer 2

First we should get everything converted to the same units. So the rectangular floor is really 550cm long and 405cm wide. So the area is 550*405= 222,750cm².

 

Then the area of 15 cm square tiles are 15*15=225cm².

 

So how many square tiles fit in the rectangular floor is a division problem- 222,750/225 = 990 tiles. 

Answer 3

We can compute the area of the floor, which is its length times its width, or:

 

A = 5.5 x 4.05 = 22.275 m²

 

The floor tiles are measured in terms of cm²

 

1 m = 100 cm

 

1 m² = 100² = 10000 cm²

 

So, 22.275 m² = 22.275 (10000) = 222,750 cm²

 

To determine exactly how many 15 cm² tiles we need, we can divide the total area of the floor (in terms of cm²) by the area of each square tile

 

If the square tiles are 15 cm, then each one covers an area of 15 x 15 = 225 cm²

 

Our computation is:

 

222,750/225 = 990 tiles are needed to cover the floor