show the speed of a ball traveling 48ms when it travel 24meters in 0.5s

Question

show the speed of a ball traveling 48ms when it travel 24meters in 0.5s

Answer 1

Hi Richard;

show the speed of a ball traveling 48ms when it travel 24meters in 0.5s

distance=48 m

rate=(24 m)/(0.5 s)

distance=(rate)(time)

48 m=[(24 m)/(0.5 s)](time)

Let's multiply both sides by (0.5 s)/(24 m)

[(0.5 s)/(24 m)](48 m)=[(0.5 s)/(24 m)][(24 m)/(0.5 s)](time)

Let's cancel where appropriate...

[(0.5 s)/(24 m)](48 m)=[(0.5 s)/(24 m)][(24 m)/(0.5 s)](time)

[(0.5 s)/(24 m)](48 m)=time

The unit of meters is in the denominator and numerator.  Let's cancel...

[(0.5 s)/(24 m)](48 m)=time

[(0.5 s)/(24)](48)=time

The only unit remaining is seconds.  This is what we need.

Let's calculate...

(48)(0.5)=24

[24/24](s)=time

1 s=time

TRAVELING AT (24 METERS)/(0.5 SECONDS), THE BALL REQUIRED 1 SECOND TO TRAVEL 48 METERS.

Answer 2

((24 m) / (0.5 s)) * (2/2) = (48 m) / (1 s) = 48 m/s