
Arturo O. answered 10/12/16
Tutor
5.0
(66)
Experienced Physics Teacher for Physics Tutoring
h(t) = 50t - 4.90t2 = t(50 - 4.90t)
When h(t) = 0, the ball is on the ground. Note that
t(50 - 4.90t) = 0 ⇒ t = 0 or t = 50/4.90 =10.20
t = 0 or 10.20
t = 0 is the instant of launch from the ground, so t = 10.20 has to be the time the ball returned to the ground. Then its total travel time in the air is 10.20 seconds.