Find an equation of the line satisfying the following conditions. Write the equation in slope-intercept form. Through (-3, 3), perpendicular to 4x + 7y = -33

Question

Through (-3, 3), perpendicular to 4x + 7y = -33

Answer 1

Hi Keith;

4x + 7y = -33

This formula is in standard form...

Ax+By=C, neither A nor B equal zero, and A is greater than zero...

Slope is -A/B.

Slope is -4/7.

The slope of the line perpendicular to this is the negative inverse...

7/4

Slope-intercept formula is...

y=mx+b

m is the slope.

b is the y-intercept, the value of y when x=0.

y=(7/4)x+b

Let's plug-in the one point provided, (-3, 3), to establish b...

3=[(7/4)(-3)]+b

3=(-21/4)+b

Let's convert 3 into 12/4...

12/4=(-21/4)+b

Let's add 21/4 to both sides...

(21/4)+(12/4)=(-21/4)+b+(21/4)

33/4=b

y=(7/4)x+33/4