
Arturo O. answered 10/10/16
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Revised question:
A rock is thrown down from a 500 foot cliff. After 1 second the rock is traveling 47 feet per second. After 3 it is traveling 111 feet per second.
A. Assume that the relationship between time, t, and speed, s, is linear and write an equation describing this relationship. Use ordered pairs of the form (t,s).
B. Use this equation to determine the speed of the rock 5 seconds after it was dropped.
(A)
The correct relation is
s(t) = s0 + at
where s(t) = speed at time t in ft/s, s0 = initial speed in ft/s, a = acceleration in ft/s2, t = time in seconds. Assume DOWN is POSITIVE direction.
s(1) = 47 ⇒ 47 = s0 + a*(1)
s(3) = 111 ⇒ 111 = s0 + a*(3)
Solve system of two linear equations in two unknowns s0 and a:
s0 + a = 47
s0 + 3a = 111
Subtract top equation from bottom equation and get
2a = 64
a = 64/2 = 32 ft/s2
Plug a = 32 into top equation and get
s0 = 47 - a = 47 - 32 = 15 ft/s
Final equation:
s(t) = 15 + 32t
(B)
When t = 5s,
s(5) = 15 + 32(5) = 175 ft/s
Will C.
If a Delorean were driven off a 500 ft cliff, it could reach 88 mph in 250 ft (90 mph @ 256 ft) and still have time to pop parachutes for a re-entry to 1985 (with an ice-proofed release mechanism).
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02/26/22
Tabitha C.
10/10/16