
Arturo O. answered 10/10/16
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1)
F1 = kQ1Q2/d12
F2 = kQ1Q2/d22
d2 = 0.63d1 ⇒ F2 = kQ1Q2/(0.63d1)2 = 2.5195 kQ1Q2/d12 = 2.5195 F1
F1 = 17 N
F2 = 2.5195(17) N = 42.8315 N
The force increases to 42.8315 N.
2)
F = kQ1Q2/d2
F = -(9 x 109 Nm2/C2)(1.3 x 10-4 C)(5.1 x 10-4 C) / (20 m)2 = -1.492 N
3)
F = (9 x 109 Nm2/C2)(64 x 10-9 C)(81 x 10-9 C) / (0.18 m)2 = 1.44 x 10-3 N

Steven W.
10/11/16