
Al P. answered 10/16/16
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Let b = boat rate in MPH
Let c = water current in MPH
From upstream trip: 6(b - c) = 528 (6 hours at the net speed of boat minus current allows him to travel 528 miles)
(divide both sides by 6): b - c = 88 (1)
From downstream trip, use the same logic, except this time you add the boat's speed to the current: 5.5(b + c) = 528
(div both sides by 5.5): b + c = 96 (2)
Notice that if you add eq (1) to eq (2):
b - c = 88
+ b + c = 96
-------------------------
2b + 0c = 184
Solve for b by dividing both sides by 2: b = 92 MPH
Use b=92 in (1) or (2) to get c = 4 MPH [ another equally valid way to get c is to follow a similar path you used to find b, except subtract (1) from (2) to get 2c = 8 ==> c = 4 ]
Check answers in (1) and (2) to make sure they make sense (they do).