Peter G. answered 10/08/16
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The space curve is
x=t
y=0
z=4t-t2.
When does this satisfy the equation z = x2+y2?
4t-t2 = t2+0
2t(t-2)=0
2t = 0 or t-2 = 0
t = 0 or t = 2
Which give points (0,0,0) and (2,0,4)
I hope that helps