If only the x is under the square root sign, then the domain of this function will be all non-negative values of x, except for where the denominator equals 0. That's because the domain of the square root of x is x greater than or equal to zero. Now, let's solve the denominator for x.
x² - 6x + 8 = 0
(x - 2)(x - 4) = 0
x = 2, 4
The domain is {[0, 2) , (2, 4) , (4, ∞)}