f(x) = (x+1)2 = x2+2x+1
f'(x) = limh→0[(f(x+h)-f(x))/h]
= limh→0[((x+h)2+2(x+h)+1 - (x2+2x+1))/h]
= limh→0[(x2+2xh+h2+2x+2h+1-x2-2x-1)/h]
= limh→0[(2xh+h2+2h)/h]
= limh→0[h(2x+h+2)/h]
= limh→0(2x+h+2) = 2x+0+2 = 2x+2