The distance that a free falling object falls is directly proportional to the square of the time it falls (before it hits the ground). If an object fell 45 ft

Question

The distance that a free falling object falls is directly proportional to the square of the time it falls (before it hits the ground). If an object fell 45 ft in 7 seconds, how far will it have fallen by the end of 8 seconds? (Leave the variation constant in fraction form or round to at least 2 decimal places. Round your final answer to the nearest foot.)

Answer 1

 

The distance fallen is directly proportional to the square of time, means distance equals time squared times some constant.

 

d = kt²

 

An object fell 45 ft in 7 seconds

d = 45 ft

t = 7 seconds

 

You are given this information so you can solve for the constant, k. Constants do not change once you solve for k, it becomes part of the equation.

 

So then you can use the k-value to solve for the distance, d fallen in 8 seconds.