A piece of aluminum foil with mass 1.65g has the length and width dimenstions of 15.0cm and 15.0cm. Using the formulas given and the literature value for the de

Question

density=2.6989

formula= mass/volume=mass/(l)(w)(t)

Answer 1

You didn't say, but I assume you are asked to find the thickness (t) of the foil.

density = mass/volume = 2.6989 g/cm³

• density = 2.6989 g/cm3
• mass = 1.65 g
• volume = l*w*t = (15 cm)(15 cm)(t)

2.6989 = 1.65/(15)(15)(t)
2.6989 = 1.65/225t
t = 1.65/(225*2.6989)

Can you finish from here?