help me with 64-y^6

Question

factor completely as a difference of squares

Answer 1

64-y^6

 

Remember how the difference of squares factors:  a²-b² = (a+b)(a-b)   [check using F-O-I-L]

 

64 = 8²  and y⁶ = (y³)²,   so (64-y⁶) = ( 8² - (y³)² )  =  ( 8 + y³ )( 8 - y³ )

Answer 2

(8-y)(8+y)