Parallel lines cut by traversal. Two alternate interior angles are congruent. m<1: x^2-10 and m<2: 4x + 11. how do I solve for x with the exponent?

Question

m<1: x²-10 and m<2: 4x + 11

 

These angles are congruent.  Solve for x to find angle in degrees.

Answer 1

Hello B,

 

You have the correct set-up:

M<1 = m<2

X² -10 = 4x + 11

 

You now have a quadratic equation.Collect all your terms over to one side then you will get

 

x² - 4x - 21 = 0

 

You can solve for x by factoring , can you do that?

 

Dont forget to check your answer for extraneous solution.