The cost c, to order n, frames, given by formula c=4n+p, where p is a constant equal to 5. What is the cost for 3 picture frames?

Question

I completely do not understand.

Answer 1

Hi Crystal!

 

This problem looks like a "tricky wording" of a normal slope-intercept form (y = mx +b) problem.

 

The equation is meant to model the cost to order a certain number of frames. In words, it looks like:

[total cost to order the frames] = $4*[number of frames] + [constant].

In the real world, the constant would be some sort of cost that is fixed for any order. The $4 would be the cost per frame.

 

Here, your equation is c = 4n + p (like y = 4x + b), and p is given to you as "a constant equal to 5." This just means that p is equal to 5, and it is a number (constant), not a variable.

So, your equation is c = 4n + 5 (like y = 4x + 5).

 

Now, you can plug in the number of picture frames given (3) for (n), and solve to find (c), the total cost of the frames.

 

c = 4(3) + 5

c = 12 + 5

c = 17

 

The cost for 3 frames is $17.

 

Hope this is helpful!

Answer 2

The cost(c) to order n frames is c=4n+p; p is 5. What is the cost for 3 picture frames?

 

Does this make more sense?

 

To calculate the cost, you follow cost=number of frames * 4 + 5