
John M. answered 08/25/16
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Certified Math Teacher with Statistics Masters
This function relies on a greatest integer function. I don't have access to the actual symbol here, but I'll use g(x) to mean the greatest integer ≤ x. (You should look it up in your text so you can use the symbol).
The function would be: f(x) = 0.39 + g(x-1). (I used x-1 since we charge a different rate for the first minute.)
The domain is all the possible times you could enter up to (but not including) 40 minutes. Therefore it would be {x|0<x<40} or (0,40) depending on which notation you'd use.
The range would be a list of all the possible charges, starting at 0.39 and jumping by 0.24 for every additional minute up to but not including 40 minutes. Therefore the range would be {0.39, 0.63, 0.87, ..., 9.75}
You didn't give enough context for the next part about ? so I'll skip forward to the last question. This function is not one-to-one, since each element in the range doesn't connect to only one element in the domain. For example, any value from 1≤x<2 would connect to $0.63 in the range.