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# factor expressions completely

I really need help solving this problem by factoring the expression completely.

3g^3 - 51g + 210g

Theanks

### 3 Answers by Expert Tutors

Barbara B. | Experienced Math, Language, Test Prep Teacher Makes Tutoring a BreezeExperienced Math, Language, Test Prep Te...
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It is really important that you remember one rule when factoring: always factor out the greatest common factor first, before factoring with grouping, etc. If you didn't make a typo, yes, add like terms first. If this is the correct problem, I would assume that your teacher is making sure you know to factor out the GCF first and that is all. That IS a form of factoring in itself. So,

3g3 - 51g + 210g
3g+ 159g
3g(g2 + 53)

By the way, as an algebra teacher of more years than I care to share : ) I have been known to give a problem like this. It does show complete understanding.

Ms. B.
Jason S. | My goal is the success of my students. Knowledge-Patience-HonestyMy goal is the success of my students. K...
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In case L from Jacksonville made a typo:

If the question were 3g^3 - 51g^2 + 210g:

3g(g^2-17g+70)

3g(g-7)(g-10)

If it were this:
3g^3 - 51g + 210g

You should add the -51g and the 210g first.

3g^3 + 159g

3(g^3 + 53)

Steve S. | Tutoring in Precalculus, Trig, and Differential CalculusTutoring in Precalculus, Trig, and Diffe...
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3g^3 - 51g + 210g =

3ggg - 3*17*g + 3*70*g =

3g(g^2 - 17 + 70) =

3g(g^2 + 53)