A dog breeder sells purebred puppies for $1200 each and adult dogs for $800 each.

Question

A dog breeder sells purebred puppies for $1200 each and adult dogs for $800 each. The breeder sells 8 dogs at a dog show for $8400. How many puppies did the breeder sell?     Please include the steps

Answer 1

Hi Craig,

Here's how you solve this problem:

D= adult dogs; P=puppies

 

 

1200P + 800D = 8400

 

P+D = 8     

D = 8 - P      (Solve for D)

 

 

1200P + 800(8 - P) = 8400               (Substitute for D)

1200P - 800P + 6400 = 8400               (Multiply)

400P + 6400 = 8400                           (Subtract)

400P = 2000                       (Subtract 6400 from both sides)

P = 5                                         (Divide both sides by 400)

This means the breeder sold 5 puppies.

 

 

Check your work!

If the breeder sold 5 puppies for $1200 each, he makes $6000.

Since the breeder sold 8 dogs total, he must have sold 3 adult dogs. At $800 each, he makes $2400.

Finally, add $2400 + $6000 = $8400.

 

Hope this helps!

-Emily