Evaluate the expression 3+10i/-8+6i, and write your answer in the form a+bi. a = and b = .

Question

Please Help Me

Answer 1

(3+10i)/(-8+6i) = ((3+10i)/(-8+6i)) * ((-8-6i)/(-8-6i))

 

                       = (1/100)(3+10i)(-8-6i)

 

                       = (1/100)(-24 -18i -80i + 60)

 

                       = (1/100)(36 -98i)

 

                       = 0.36 - 0.98i

From here I'll let determine what a and b.

Answer 2

Hi Bino

 

You have to multiply the numerator and dividend by the complex conjugate of (-8 + 6i), as shown:

 

   (3 + 10i)       (-8 - 6i)          (3 + 10i) (-8 - 6i)       -24 -18i -80i - 60i²       -24 - 98i + 60

--------------- --------------  =  ---------------------  =  ---------------------- =  ------------------

   (-8 + 6i)       (-8 - 6i)           (-8)² - (36)*(i²)                64 + 36                       100

 

 

 

The solution is:    (3+10i)/(-8+6i) =  (36 - 98i )/100   =  (18 - 49i )/50

 

 

Answer 3

Multiply the fraction by (-8-6i)/(-8-6i) to remove i from the denominator.

 

(3+10i)(-8-6i)/(-8+6i)(-8-6i)

 

(-24-18i-80i-60i²)/(64+48i-48i-36i²)

 

(-24-98i+60)/(64+36)

 

(36-98i/100

 

(9/25)ui - 49/50

Answer 4

Multiply both the numerator and denominator by the conjugate of the denominator.  Doing this will eliminate the complex denominator since we need to put it in the designated form.