a farmer has 18 more horses than cows.there are 13 fewer cows and than sheep.there are 15 cows.how many more horses does the farmer have than sheep?

Question

I tried adding and subyracting.

Answer 1

Let h = horses, c = cows, and s= sheep

 

'18 more horses than cows'  ---> c +18   = h    (1)

 

'13 fewer cows than sheep'  ---> s   = c +13   (2)

 

'15 cows'                            ---->      c    = 15

 

'how many more horses than sheep' ----> h-s = ?

 

Given than c =15, from (1) 15+ 18 = h = 33

 

and from (2), s = 15 +13 = 28

 

Therefore, h - s = 33 - 28 = 5

 

So there are 5 more horses than sheep

Answer 2

h - number of horses.

 

C - number of cows

S  - number of Sheep

 

 

   h = 18 + C

   C = S - 13

 

   h = 18 +15 = 33

 

    15 = S - 13

 

     S = 28

 

     33 - 28 = 5

   This is an example of System of equation , that is solved by back Substitution.