
Arturo O. answered 07/15/16
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You can set this up as an exponential decay problem.
Amount of isotope remaining:
N(t) = N(0)e-kt
t1/2 = 6 days
N(t + t1/2) = (1/2) N(t)
N(0)e-kte-kt1/2 = (1/2) N(0)e-kt
e-6k = 1/2
k = -ln(0.5) / 6 = 0.1155 days-1
N(t) = N(0)e-0.1155t
Let T = time when N = 9% = 0.09
0.09 = 1*e-0.1155T
T = -ln(0.09) / 0.1155 = 20.848 days